Regex & PHP - isolate src attribute from img tag


Question

With PHP, how can I isolate the contents of the src attribute from $foo? The end result I'm looking for would give me just "http://example.com/img/image.jpg"

$foo = '<img class="foo bar test" title="test image" src="http://example.com/img/image.jpg" alt="test image" width="100" height="100" />';
1
35
1/22/2010 9:47:46 PM

Accepted Answer

If you don't wish to use regex (or any non-standard PHP components), a reasonable solution using the built-in DOMDocument class would be as follows:

<?php
    $doc = new DOMDocument();
    $doc->loadHTML('<img src="http://example.com/img/image.jpg" ... />');
    $imageTags = $doc->getElementsByTagName('img');

    foreach($imageTags as $tag) {
        echo $tag->getAttribute('src');
    }
?>
70
1/22/2010 10:14:05 PM

Code

<?php
    $foo = '<img class="foo bar test" title="test image" src="http://example.com/img/image.jpg" alt="test image" width="100" height="100" />';
    $array = array();
    preg_match( '/src="([^"]*)"/i', $foo, $array ) ;
    print_r( $array[1] ) ;

Output

http://example.com/img/image.jpg

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