PHP, get file name without file extension


Question

I have this PHP code:

function ShowFileExtension($filepath)
{
    preg_match('/[^?]*/', $filepath, $matches);
    $string = $matches[0];

    $pattern = preg_split('/\./', $string, -1, PREG_SPLIT_OFFSET_CAPTURE);

    if(count($pattern) > 1)
    {
        $filenamepart = $pattern[count($pattern)-1][0];
        preg_match('/[^?]*/', $filenamepart, $matches);
        return strtolower($matches[0]);
    }
}

If I have a file named my.zip, this function returns .zip.

I want to do the reverse, I want the function to return my without the extension.

The file is just a string in a variable.

1
173
12/17/2014 10:42:48 PM

Accepted Answer

No need for all that. Check out pathinfo(), it gives you all the components of your path.

Example from the manual:

$path_parts = pathinfo('/www/htdocs/index.html');

echo $path_parts['dirname'], "\n";
echo $path_parts['basename'], "\n";
echo $path_parts['extension'], "\n";
echo $path_parts['filename'], "\n"; // filename is only since PHP 5.2.0

Output of the code:

/www/htdocs
index.html
html
index

And alternatively you can get only certain parts like:

echo pathinfo('/www/htdocs/index.html', PATHINFO_EXTENSION); // outputs html
339
7/30/2016 6:39:41 PM

As an alternative to pathinfo(), you can use

  • basename() — Returns filename component of path

Example from PHP manual

$path = "/home/httpd/html/index.php";
$file = basename($path);         // $file is set to "index.php"
$file = basename($path, ".php"); // $file is set to "index"

You have to know the extension to remove it in advance though.

However, since your question suggests you have the need for getting the extension and the basename, I'd vote Pekka's answer as the most useful one, because it will give you any info you'd want about the path and file with one single native function.


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