Dynamically display a CSV file as an HTML table on a web page


I'd like to take a CSV file living server-side and display it dynamically as an html table. E.g., this:

Name, Age, Sex
"Cantor, Georg", 163, M

should become this:

<tr> <td>Name</td> <td>Age</td> <td>Sex</td> </tr>
<tr> <td>Cantor, Georg</td> <td>163</td> <td>M</td> </td>

Solutions in any language are welcome.

2/6/2009 4:54:22 AM

Accepted Answer

The previously linked solution is a horrible piece of code; nearly every line contains a bug. Use fgetcsv instead:

echo "<html><body><table>\n\n";
$f = fopen("so-csv.csv", "r");
while (($line = fgetcsv($f)) !== false) {
        echo "<tr>";
        foreach ($line as $cell) {
                echo "<td>" . htmlspecialchars($cell) . "</td>";
        echo "</tr>\n";
echo "\n</table></body></html>";
12/26/2015 8:00:28 PM

Here is a simple function to convert csv to html table using php:

function jj_readcsv($filename, $header=false) {
$handle = fopen($filename, "r");
echo '<table>';
//display header row if true
if ($header) {
    $csvcontents = fgetcsv($handle);
    echo '<tr>';
    foreach ($csvcontents as $headercolumn) {
        echo "<th>$headercolumn</th>";
    echo '</tr>';
// displaying contents
while ($csvcontents = fgetcsv($handle)) {
    echo '<tr>';
    foreach ($csvcontents as $column) {
        echo "<td>$column</td>";
    echo '</tr>';
echo '</table>';

One can call this function like jj_readcsv('image_links.csv',true);

if second parameter is true then the first row of csv will be taken as header/title.

Hope this helps somebody. Please comment for any flaws in this code.

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