Checking if the string is empty


Question

I have a function isNotEmpty which returns true if the string is not empty and false if the string is empty. I've found out that it is not working if I pass an empty string through it.

function isNotEmpty($input) 
{
    $strTemp = $input;
    $strTemp = trim($strTemp);

    if(strTemp != '') //Also tried this "if(strlen($strTemp) > 0)"
    {
         return true;
    }

    return false;
}

The validation of the string using isNotEmpty is done:

if(isNotEmpty($userinput['phoneNumber']))
{
    //validate the phone number
}
else
{
    echo "Phone number not entered<br/>";
}

If the string is empty the else doesn't execute, I don't understand why, can someone please shed some light on this please.

1
204
4/5/2009 2:18:11 PM

Accepted Answer

Simple problem actually. Change:

if (strTemp != '')

to

if ($strTemp != '')

Arguably you may also want to change it to:

if ($strTemp !== '')

since != '' will return true if you pass is numeric 0 and a few other cases due to PHP's automatic type conversion.

You should not use the built-in empty() function for this; see comments and the PHP type comparison tables.

288
1/16/2019 4:28:54 AM

PHP have a built in function called empty() the test is done by typing if(empty($string)){...} Reference php.net : php empty


Licensed under: CC-BY-SA with attribution
Not affiliated with: Stack Overflow
Icon